Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q87
If the standard deviation of the numbers -1,0,1, k is √ 5 where k >0, then k is equal to:
If the standard deviation of the numbers $\displaystyle -1,0,1, \mathrm{k}$ is $\displaystyle \sqrt{5}$ where $\displaystyle \mathrm{k}>0$, then k is equal to :
Official answer
(3)
$\displaystyle 2 \sqrt{6}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.