Mathematics · 2024
JEE Main · 27 January 2024, Shift 1 · Q27
If the solution of the differential equation (2 x+3 y-2) d x+(4 x+6 y-7) d y=0, y(0)=3, is α x+β y+3 log_e |2 x+3 y-γ|=6, then α+2 β+3 γ is equal to…
If the solution of the differential equation $\displaystyle (2 x+3 y-2) \mathrm{d} x+(4 x+6 y-7) \mathrm{d} y=0, y(0)=3$, is $\displaystyle \alpha x+\beta y+3 \log _{\mathrm{e}}|2 x+3 y-\gamma|=6$, then $\displaystyle \alpha+2 \beta+3 \gamma$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
29
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.