Mathematics · 2025
JEE Main · 2 April 2025, Shift 2 · Q21
If the set of all a ∈ R -{1}, for which the roots of the equation (1- a ) x^2+2( a -3) x+9=0 are positive is (-∞,-α] ∪[β, γ), then 2 α+β+γ is equal…
If the set of all $\displaystyle \mathrm{a} \in \mathbf{R}-\{1\}$, for which the roots of the equation $\displaystyle (1-\mathrm{a}) x^2+2(\mathrm{a}-3) x+9=0$ are positive is $\displaystyle (-\infty,-\alpha] \cup[\beta, \gamma)$, then $\displaystyle 2 \alpha+\beta+\gamma$ is equal to $\displaystyle \_\_\_\_$.
Official answer
From NTA’s final answer key for this paper.
7
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.