Mathematics · 2023
JEE Main · 8 April 2023, Shift 1 · Q17
If the points with position vectors α i +10 j +13 k, 6 i +11 j +11 k, 9/2 i +β j -8 k are collinear, then (19 α-6 β)^2 is equal to
If the points with position vectors $\displaystyle \alpha \hat{i}+10 \hat{j}+13 \hat{k}, 6 \hat{i}+11 \hat{j}+11 \hat{k}, \frac{9}{2} \hat{i}+\beta \hat{j}-8 \hat{k}$ are collinear, then $\displaystyle (19 \alpha-6 \beta)^2$ is equal to
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 36$
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JEE Main 2023 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.