Mathematics · 2019
JEE Main · 10 April 2019, Shift 2 · Q80
If the line a x+y= c, touches both the curves x^2+y^2=1 and y^2=4 √ 2 x, then |c| is equal to:
If the line $\displaystyle \mathrm{a} x+y=\mathrm{c}$, touches both the curves $\displaystyle x^2+y^2=1$ and $\displaystyle y^2=4 \sqrt{2} x$, then $\displaystyle |c|$ is equal to :
Official answer
(1)
$\displaystyle \sqrt{2}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.