Mathematics · 2019
JEE Main · 9 April 2019, Shift 1 · Q82
If the line y= m x+7 √ 3 is normal to the hyperbola x^2/24-y^2/18=1, then a value of m is:
If the line $\displaystyle y=\mathrm{m} x+7 \sqrt{3}$ is normal to the
hyperbola $\displaystyle \frac{x^2}{24}-\frac{y^2}{18}=1$, then a value of
m is :
Official answer
(1)
$\displaystyle \frac{2}{\sqrt{5}}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.