Offline paper
Mathematics · 2015
JEE Main 2015 · 2015-04-04 Offline · Q71
If the function. g(x)= {k √(x+1), 0 ≤ x ≤ 3; m x+2, 3<x ≤ 5} is differentiable, then the value of k+ m is:
If the function.
$$g(x)= \begin{cases}k \sqrt{x+1} & , 0 \leq x \leq 3 \\ \operatorname{m} x+2 & , 3<x \leq 5\end{cases}
$$
is differentiable, then the value of $\displaystyle k+\mathrm{m}$ is :
Official answer
(1)
$\displaystyle 2$
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JEE Main 2015 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.