Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q71
If the function f(x)= {-x, x<1; a+ cos^-1(x+b), 1 ≤ x ≤ 2} is differentiable at x=1, then a/b is equal to:
If the function
$$f(x)= \begin{cases}-x, & x<1 \\ a+\cos ^{-1}(x+b), & 1 \leq x \leq 2\end{cases}
$$
is differentiable at $\displaystyle x=1$, then $\displaystyle \frac{a}{b}$ is equal to :
Official answer
(3)
$\displaystyle \frac{\pi+2}{2}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.