Mathematics · 2019
JEE Main · 9 April 2019, Shift 2 · Q71
If the function f(x)= {a |π-x|+1, x ≤ 5; b |x-π|+3, x>5} is continuous at x=5, then the value of a - b is:
If the function $\displaystyle f(x)=\left\{\begin{array}{l}\mathrm{a}|\pi-x|+1, x \leq 5 \\ \mathrm{~b}|x-\pi|+3, x>5\end{array}\right.$ is continuous at $\displaystyle x=5$, then the value of $\displaystyle \mathrm{a}-\mathrm{b}$ is :
Official answer
(3)
$\displaystyle \frac{2}{5-\pi}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.