Mathematics · 2018
JEE Main · 16 April 2018, Shift 1 · Q71
If the function f defined as f(x)=1/x-(k -1)/(e^2 x-1), x ≠ 0, is continuous at x=0, then the ordered pair ( k, f(0)) is equal to:
If the function $\displaystyle f$ defined as $\displaystyle f(x)=\frac{1}{x}-\frac{\mathrm{k}-1}{\mathrm{e}^{2 x}-1}, x \neq 0$, is continuous at $\displaystyle x=0$, then the ordered pair $\displaystyle (\mathrm{k}, f(0))$ is equal to :
Official answer
(2)
$\displaystyle (3,1)$
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JEE Main 2018 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.