Mathematics · 2016
JEE Main · 9 April 2016, Shift 1 · Q63
If the equations x^2+b x-1=0 and x^2+x+b=0 have a common root different from -1, then |b| is equal to:
If the equations $\displaystyle x^2+b x-1=0$ and $\displaystyle x^2+x+b=0$ have a common root different from -$\displaystyle 1$ , then $\displaystyle |b|$ is equal to :
Official answer
(4)
$\displaystyle \sqrt{3}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.