Mathematics · 2025
JEE Main · 24 January 2025, Shift 2 · Q12
If the equation of the parabola with vertex V (3/2, 3) and the directrix x+2 y=0 is α x^2+β y^2-γ x y-30 x-60 y+225=0, then α+β+γ is equal to:
If the equation of the parabola with vertex $\displaystyle \mathrm{V}\left(\frac{3}{2}, 3\right)$ and the directrix $\displaystyle x+2 y=0$ is $\displaystyle \alpha x^2+\beta y^2-\gamma x y-30 x-60 y+225=0$, then $\displaystyle \alpha+\beta+\gamma$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle 9$
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JEE Main 2025 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.