Mathematics · 2022
JEE Main · 27 June 2022, Shift 2 · Q11
If the equation of the parabola, whose vertex is at (5,4) and the directrix is 3 x+y-29=0, is x^2+a y^2+b x y+ c x+d y+k=0, then a+b+c+d+k is equal to
If the equation of the parabola, whose vertex is at $\displaystyle (5,4)$ and the directrix is $\displaystyle 3 x+y-29=0$, is $\displaystyle x^2+a y^2+b x y+\mathrm{c} x+d y+k=0$, then $\displaystyle a+b+c+d+k$ is equal to
Official answer
(4)
$\displaystyle -576$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.