Mathematics · 2026
JEE Main · 21 January 2026, Shift 1 · Q7
If the coefficient of x in the expansion of ( a x^2+ b x+ c )(1-2 x)^26 is -56 and the coefficients of x^2 and x^3 are both zero, then a + b + c is…
If the coefficient of $\displaystyle x$ in the expansion of $\displaystyle \left(\mathrm{a} x^2+\mathrm{b} x+\mathrm{c}\right)(1-2 x)^{26}$ is -$\displaystyle 56$ and the coefficients of $\displaystyle x^2$ and $\displaystyle x^3$ are both zero, then $\displaystyle \mathrm{a}+\mathrm{b}+\mathrm{c}$ is equal to :
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 1403$
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JEE Main 2026 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.