Mathematics · 2019
JEE Main · 9 January 2019, Shift 2 · Q80
If the circles x^2+y^2-16 x-20 y+164= r^2 and (x-4)^2+(y-7)^2=36 intersect at two distinct points, then:
If the circles $\displaystyle x^2+y^2-16 x-20 y+164=\mathbf{r}^2$ and $\displaystyle (x-4)^2+(y-7)^2=36$ intersect at two distinct points, then :
Official answer
(1)
$\displaystyle 1<\mathrm{r}<11$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.