Mathematics · 2019
JEE Main · 10 April 2019, Shift 1 · Q79
If the circles x^2+y^2+5 K x+2 y+ K =0 and 2(x^2+y^2)+2 K x+3 y-1=0,( K ∈ R ), intersect at the points P and Q, then the line 4 x+5 y- K =0 passes…
If the circles $\displaystyle x^2+y^2+5 \mathrm{~K} x+2 y+\mathrm{K}=0$ and $\displaystyle 2\left(x^2+y^2\right)+2 \mathrm{~K} x+3 y-1=0,(\mathrm{~K} \in \mathbf{R})$, intersect at the points P and Q, then the line $\displaystyle 4 x+5 y-\mathrm{K}=0$ passes through P and Q , for:
Official answer
(4)
no value of $\displaystyle K$.
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.