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Mathematics · 2013

JEE Main · 23 April 2013, Shift 1 · Q68

If the circle x^2+y^2-6 x-8 y+(25- a^2)=0 touches the axis of x, then a equals.

If the circle $\displaystyle x^2+y^2-6 x-8 y+\left(25-\mathrm{a}^2\right)=0$ touches the axis of $\displaystyle x$, then a equals.
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JEE Main 2013 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.