Mathematics · 2019
JEE Main · 11 January 2019, Shift 2 · Q81
If the area of the triangle whose one vertex is at the vertex of the parabola, y^2+4(x- a^2)=0 and the other two vertices are the points of…
If the area of the triangle whose one vertex is at the vertex of the parabola, $\displaystyle y^2+4\left(x-\mathbf{a}^2\right)=0$ and the other two vertices are the points of intersection of the parabola and $\displaystyle y$-axis, is $\displaystyle 250$ sq. units, then a value of ' a ' is :
Official answer
(3)
$\displaystyle 5$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.