Mathematics · 2019
JEE Main · 10 January 2019, Shift 2 · Q80
If the area of an equilateral triangle inscribed in the circle, x^2+y^2+10 x+12 y+ c =0 is 27 √ 3 sq. units then c is equal to:
If the area of an equilateral triangle inscribed in the circle, $\displaystyle x^2+y^2+10 x+12 y+\mathrm{c}=0$ is $\displaystyle 27 \sqrt{3}$ sq. units then c is equal to :
Official answer
(3)
$\displaystyle 25$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.