Mathematics · 2020
JEE Main · 9 January 2020, Shift 2 · Q66
If one end of a focal chord AB of the parabola y^2=8 x is at A (1/2,-2), then the equation of the tangent to it at B is:
If one end of a focal chord AB of the parabola $\displaystyle y^2=8 x$ is at $\displaystyle \mathrm{A}\left(\frac{1}{2},-2\right)$, then the equation of the tangent to it at $\displaystyle B$ is :
Official answer
(3)
$\displaystyle x-2 y+8=0$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.