Mathematics · 2024
JEE Main · 27 January 2024, Shift 2 · Q13
If y=y(x) is the solution curve of the differential equation (x^2-4) d y-(y^2-3 y) d x=0, x>2, y(4)=3/2 and the slope of the curve is never zero,…
If $\displaystyle y=y(x)$ is the solution curve of the differential equation $\displaystyle \left(x^2-4\right) \mathrm{d} y-\left(y^2-3 y\right) \mathrm{d} x=0, x>2, y(4)=\frac{3}{2}$ and the slope of the curve is never zero, then the value of $\displaystyle y(10)$ equals :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle \frac{3}{1+(8)^{1 / 4}}$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.