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Mathematics · 2019

JEE Main · 10 April 2019, Shift 1 · Q71

If f(x)= {(sin ( p +1) x+ sin x)/x, x<0; q, x=0; (√(x+x^2)-√ x)/(x^3 / 2), x>0} is continuous at x=0, then the ordered pair ( p, q ) is equal to:

If $\displaystyle f(x)=\left\{\begin{array}{cc}\frac{\sin (\mathrm{p}+1) x+\sin x}{x} & , \quad x<0 \\ \mathrm{q} & , \quad x=0 \\ \frac{\sqrt{x+x^2}-\sqrt{x}}{x^{3 / 2}} & , \quad x>0\end{array}\right.$ is continuous at $\displaystyle x=0$, then the ordered pair $\displaystyle (\mathrm{p}, \mathrm{q})$ is equal to :
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.