Mathematics · 2020
JEE Main · 9 January 2020, Shift 1 · Q58
If f(x)= {(sin ( a +2) x+ sin x)/x; x<0; b; x=0; ((x+3 x^2)^1 / 3-x^1 / 3)/(x^4 / 3); x>0} is continuous at x=0, then a +2 b is equal to:
If $\displaystyle f(x)=\left\{\begin{array}{cl}\frac{\sin (\mathrm{a}+2) x+\sin x}{x} & ; x<0 \\ \mathrm{~b} & ; x=0 \\ \frac{\left(x+3 x^2\right)^{1 / 3}-x^{1 / 3}}{x^{4 / 3}} & ; x>0\end{array}\right.$
is continuous at $\displaystyle x=0$, then a +$\displaystyle 2$ b is equal
to :
Official answer
(2)
$\displaystyle 0$
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.