Mathematics · 2016
JEE Main · 10 April 2016, Shift 1 · Q62
If x is a solution of the equation, √(2 x+1)-√(2 x-1)=1,(x ≥ 1/2), then √(4 x^2-1) is equal to:
If $\displaystyle x$ is a solution of the equation, $\displaystyle \sqrt{2 x+1}-\sqrt{2 x-1}=1,\left(x \geqslant \frac{1}{2}\right)$, then $\displaystyle \sqrt{4 x^2-1}$ is equal to :
Official answer
(1)
$\displaystyle \frac{3}{4}$
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JEE Main 2016 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.