Mathematics · 2024
JEE Main · 30 January 2024, Shift 1 · Q20
If 2 sin^3 x+ sin 2 x cos x+4 sin x-4=0 has exactly 3 solutions in the interval [0, (n π)/2], n ∈ N, then the roots of the equation x^2+n x+(n-3)=0…
If $\displaystyle 2 \sin ^3 x+\sin 2 x \cos x+4 \sin x-4=0$ has exactly $\displaystyle 3$ solutions in the interval $\displaystyle \left[0, \frac{\mathrm{n} \pi}{2}\right], \mathrm{n} \in \mathrm{N}$, then the roots of the equation $\displaystyle x^2+n x+(n-3)=0$ belong to :
Official answer
From NTA’s final answer key for this paper.
(3)
$\displaystyle (-\infty, 0)$
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JEE Main 2024 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.