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Mathematics · 2014

JEE Main 2014 · 2014-04-06 Offline · Q61

If X={4^n-3 n-1: n ∈ N} and Y ={9( n -1): n ∈ N }, where N is the set of natural numbers, then X ∪ Y is equal to:

If $\displaystyle X=\left\{4^n-3 n-1: n \in N\right\}$ and $\displaystyle \mathrm{Y}=\{9(\mathrm{n}-1): \mathrm{n} \in \mathrm{N}\}$, where N is the set of natural numbers, then $\displaystyle \mathrm{X} \cup \mathrm{Y}$ is equal to :
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.