If A= [1, 5; λ, 10], A^-1=α A+β I and α+β=-2, then 4 α^2+β^2+λ^2 is equal to:

If $\displaystyle A=\left[\begin{array}{cc}1 & 5 \\ \lambda & 10\end{array}\right], A^{-1}=\alpha A+\beta I$ and $\displaystyle \alpha+\beta=-2$, then $\displaystyle 4 \alpha^2+\beta^2+\lambda^2$ is equal to :