Mathematics · 2022
JEE Main · 25 June 2022, Shift 1 · Q16
If y= m_1 x+ c_1 and y= m_2 x+ c_2, m_1 ≠ m_2 are two common tangents of circle x^2+y^2=2 and parabola y^2=x, then the value of 8| m_1 m_2| is equal…
If $\displaystyle y=\mathrm{m}_1 x+\mathrm{c}_1$ and $\displaystyle y=\mathrm{m}_2 x+\mathrm{c}_2, \mathrm{~m}_1 \neq \mathrm{m}_2$ are two common tangents of circle $\displaystyle x^2+y^2=2$ and parabola $\displaystyle y^2=x$, then the value of $\displaystyle 8\left|\mathrm{~m}_1 \mathrm{~m}_2\right|$ is equal to :
Official answer
(3)
$\displaystyle -4+3 \sqrt{2}$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.