Mathematics · 2017
JEE Main · 8 April 2017, Shift 1 · Q73
If a point P has co-ordinates (0, -2) and Q is any point on the circle, x^2+y^2-5 x-y+5=0, then the maximum value of ( PQ )^2 is:
If a point P has co-ordinates $\displaystyle (0, -2)$ and Q is any point on the circle, $\displaystyle x^2+y^2-5 x-y+5=0$, then the maximum value of $\displaystyle (\mathrm{PQ})^2$ is :
Official answer
(2)
$\displaystyle 14+5 \sqrt{3}$
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JEE Main 2017 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.