Mathematics · 2014
JEE Main · 9 April 2014, Shift 1 · Q80
Given three points P, Q, R with P(5, 3) and R lies on the x -axis. If equation of RQ is x-2 y=2 and PQ is parallel to the x -axis, then the centroid…
Given three points P, Q, R with P$\displaystyle (5, 3)$ and R lies on the $\displaystyle x$-axis. If equation of RQ is $\displaystyle x-2 y=2$ and PQ is parallel to the $\displaystyle x$-axis, then the centroid of $\displaystyle \triangle \mathrm{PQR}$ lies on the line :
Official answer
(4)
$\displaystyle 2 x-5 y=0$
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JEE Main 2014 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.