Mathematics · 2021
JEE Main · 18 March 2021, Shift 1 · Q76
For the four circles M, N, O and P, following four equations are given: Circle M: x^2+y^2=1 Circle N: x^2+y^2-2 x=0 Circle O: x^2+y^2-2 x-2 y+1=0…
For the four circles $\displaystyle \mathrm{M}, \mathrm{N}, \mathrm{O}$ and P , following four equations are given :
Circle M : $\displaystyle x^2+y^2=1$
Circle $\displaystyle \mathrm{N}: x^2+y^2-2 x=0$
Circle $\displaystyle \mathrm{O}: x^2+y^2-2 x-2 y+1=0$
Circle P : $\displaystyle x^2+y^2-2 y=0$
If the centre of circle M is joined with centre of the circle N , further centre of circle N is joined with centre of the circle O, centre of circle O is joined with the centre of circle P and lastly, centre of circle P is joined with centre of circle M , then these lines form the sides of a :
Official answer
(3)
Square
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.