Mathematics · 2019
JEE Main · 9 January 2019, Shift 1 · Q79
Equation of a common tangent to the circle, x^2+y^2-6 x=0 and the parabola, y^2=4 x, is:
Equation of a common tangent to the circle, $\displaystyle x^2+y^2-6 x=0$ and the parabola, $\displaystyle y^2=4 x$, is :
Official answer
(4)
$\displaystyle \sqrt{3} y=x+3$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.