Mathematics · 2022
JEE Main · 30 June 2022, Shift 1 · Q14
Consider three circles: C_1: x^2+y^2= r^2; C_2:(x-1)^2+(y-1)^2= r^2; C_3:(x-2)^2+(y-1)^2= r^2 If a line L: y= m x+ c be a common tangent to C_1, C_2…
Consider three circles :
$$\begin{aligned}
& \mathrm{C}_1: x^2+y^2=\mathrm{r}^2 \\
& \mathrm{C}_2:(x-1)^2+(y-1)^2=\mathrm{r}^2 \\
& \mathrm{C}_3:(x-2)^2+(y-1)^2=\mathrm{r}^2
\end{aligned}
$$
If a line $\displaystyle \mathrm{L}: y=\mathrm{m} x+\mathrm{c}$ be a common tangent to $\displaystyle \mathrm{C}_1, \mathrm{C}_2$ and $\displaystyle \mathrm{C}_3$ such that $\displaystyle \mathrm{C}_1$ and $\displaystyle \mathrm{C}_3$ lie on one side of line L while $\displaystyle \mathrm{C}_2$ lies on other side, then the value of $\displaystyle 20\left(\mathrm{r}^2+\mathrm{c}\right)$ is equal to :
Official answer
(4)
$\displaystyle 6$
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JEE Main 2022 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.