Mathematics · 2021
JEE Main · 22 July 2021, Shift 2 · Q89
Consider the following frequency distribution: If mean =309/22 and median =14, then the value ( a - b )^2 is equal to \ \ \ \.
Consider the following frequency distribution :
If mean $\displaystyle =\frac{309}{22}$ and median $\displaystyle =14$, then the value $\displaystyle (\mathrm{a}-\mathrm{b})^2$ is equal to \_\_\_\_.
| Class : | $\displaystyle 0-6$ | $\displaystyle 6-12$ | $\displaystyle 12-18$ | $\displaystyle 18-24$ | $\displaystyle 24-30$ |
| Frequency : | a | b | $\displaystyle 12$ | $\displaystyle 9$ | $\displaystyle 5$ |
Official answer
4
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.