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Mathematics · 2021

JEE Main · 22 July 2021, Shift 2 · Q89

Consider the following frequency distribution: If mean =309/22 and median =14, then the value ( a - b )^2 is equal to \ \ \ \.

Consider the following frequency distribution :
Class :$\displaystyle 0-6$$\displaystyle 6-12$$\displaystyle 12-18$$\displaystyle 18-24$$\displaystyle 24-30$
Frequency :ab$\displaystyle 12$$\displaystyle 9$$\displaystyle 5$
If mean $\displaystyle =\frac{309}{22}$ and median $\displaystyle =14$, then the value $\displaystyle (\mathrm{a}-\mathrm{b})^2$ is equal to \_\_\_\_.
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.