Mathematics · 2021
JEE Main · 27 July 2021, Shift 2 · Q63
Consider a circle C which touches the y -axis at (0,6) and cuts off an intercept 6 √ 5 on the x -axis. Then the radius of the circle C is equal to:
Consider a circle $\displaystyle C$ which touches the $\displaystyle y$-axis at $\displaystyle (0,6)$ and cuts off an intercept $\displaystyle 6 \sqrt{5}$ on the $\displaystyle x$-axis. Then the radius of the circle $\displaystyle C$ is equal to :
Official answer
(3)
$\displaystyle 9$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.