Mathematics · 2019
JEE Main · 10 April 2019, Shift 1 · Q89
ABC is a triangular park with AB = AC =100 metres. A vertical tower is situated at the mid-point of BC. If the angles of elevation of the top of the…
ABC is a triangular park with $\displaystyle \mathrm{AB}=\mathrm{AC}=100$ metres. A vertical tower is situated at the mid-point of BC. If the angles of elevation of the top of the tower at A and B are $\displaystyle \cot ^{-1}(3 \sqrt{2})$ and $\displaystyle \operatorname{cosec}^{-1}(2 \sqrt{2})$ respectively, then the height of the tower (in metres) is :
Official answer
(3)
$\displaystyle 20$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.