Mathematics · 2019
JEE Main · 11 January 2019, Shift 1 · Q80
A square is inscribed in the circle x^2+y^2-6 x+8 y-103=0 with its sides parallel to the coordinate axes. Then the distance of the vertex of this…
A square is inscribed in the circle $\displaystyle x^2+y^2-6 x+8 y-103=0$ with its sides parallel to the coordinate axes. Then the distance of the vertex of this square which is nearest to the origin is :
Official answer
(2)
$\displaystyle \sqrt{41}$
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JEE Main 2019 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.