Mathematics · 2021
JEE Main · 26 February 2021, Shift 2 · Q79
A natural number has prime factorization given by n =2^x 3^y 5^z, where y and z are such that y+z=5 and y^-1+z^-1=5/6, y>z. Then the number of odd…
A natural number has prime factorization given by $\displaystyle \mathrm{n}=2^x 3^y 5^z$, where $\displaystyle y$ and $\displaystyle z$ are such that $\displaystyle y+z=5$ and $\displaystyle y^{-1}+z^{-1}=\frac{5}{6}, y>z$. Then the number of odd divisors of n, including $\displaystyle 1$, is:
Official answer
(3)
$\displaystyle 12$
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JEE Main 2021 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.