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Mathematics · 2020

JEE Main · 2 September 2020, Shift 1 · Q65

A line parallel to the straight line 2 x-y=0 is tangent to the hyperbola x^2/4-y^2/2=1 at the point (x_1, y_1). Then x_1^2+5 y_1^2 is equal to:

A line parallel to the straight line $\displaystyle 2 x-y=0$ is tangent to the hyperbola $\displaystyle \frac{x^2}{4}-\frac{y^2}{2}=1$ at the point $\displaystyle \left(x_1, y_1\right)$. Then $\displaystyle x_1^2+5 y_1^2$ is equal to :
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JEE Main 2020 Mathematics question, with the answer from NTA’s final answer key. Where our answers come from.