Chemistry · 2023
JEE Main · 31 January 2023, Shift 1 · Q50
When Cu^2+ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is…
When $\displaystyle \mathrm{Cu}^{2+}$ ion is treated with KI, a white precipitate, X appears in solution. The solution is titrated with sodium thiosulphate, the compound Y is formed. X and Y respectively are
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \mathrm{X}=\mathrm{Cu}_2 \mathrm{I}_2 \quad \mathrm{Y}=\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$
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JEE Main 2023 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.