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Chemistry · 2021

JEE Main · 25 July 2021, Shift 1 · Q51

When 10 mL of an aqueous solution of Fe^2+ ions was titrated in the presence of dil H_2 SO_4 using diphenylamine indicator, 15 mL of 0.02 M solution…

When $\displaystyle 10$ mL of an aqueous solution of $\displaystyle \mathrm{Fe}^{2+}$ ions was titrated in the presence of dil $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ using diphenylamine indicator, $\displaystyle 15$ mL of $\displaystyle 0.02$ M solution of $\displaystyle \mathrm{K}_2 \mathrm{Cr}_2 \mathrm{O}_7$ was required to get the end point. The molarity of the solution containing $\displaystyle \mathrm{Fe}^{2+}$ ions is $\displaystyle x \times 10^{-2} \mathrm{M}$. The value of $\displaystyle x$ is \_\_\_\_. (Nearest integer)
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.