Chemistry · 2019
JEE Main · 12 April 2019, Shift 1 · Q57
What is the molar solubility of Al ( OH )_3 in 0.2 M NaOH solution? Given that, solubility product of Al ( OH )_3=2.4 × 10^-24:
What is the molar solubility of $\displaystyle \mathrm{Al}(\mathrm{OH})_3$ in $\displaystyle 0.2$ M NaOH solution ? Given that, solubility product of $\displaystyle \mathrm{Al}(\mathrm{OH})_3=2.4 \times 10^{-24}$ :
Official answer
(1)
$\displaystyle 3 \times 10^{-22}$
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