Chemistry · 2022
JEE Main · 29 June 2022, Shift 1 · Q73
Two isomers 'A' and 'B' with molecular formula C_4 H_8 give different products on oxidation with KMnO_4 in acidic medium. Isomer 'A' on reaction with…
Two isomers 'A' and 'B' with molecular formula $\displaystyle \mathrm{C}_4 \mathrm{H}_8$ give different products on oxidation with $\displaystyle \mathrm{KMnO}_4$ in acidic medium. Isomer 'A' on reaction with $\displaystyle \mathrm{KMnO}_4 / \mathrm{H}^{+}$ results in effervescence of a gas and gives ketone. The compound 'A' is
Official answer
(4)
$\displaystyle 2$-methyl propene.
More from Hydrocarbons
- The reactions which produce alcohol as the product are: A. CH_4+O_2 →[Δ]Mo_2 O_3 B. 2 CH_3 CH_3+3 O_2 →[Δ](CH_3 COO)_2 Mn C. (CH_3)_3 CH →KMnO_4 D. 2…2026
- In the following sequence of reactions, the final product D is:2021
- Among the following, the aromatic compounds are: Choose the correct answer from the following options:2021
- An unsaturated hydrocarbon X absorbs two hydrogen molecules on catalytic hydrogenation, and also gives following reaction: X →[Zn / H_2 O]O_3 A…2020
- Total number of aromatic compounds among the following compounds is ____.2024
- The major product of the following reaction is:2020
- Match List - I with List - II. Choose the correct answer from the options given below:2025
- An optically active alkyl halide C_4 H_9 Br[A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product which reacts with…2025
JEE Main 2022 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.