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Chemistry · 2020

JEE Main · 3 September 2020, Shift 2 · Q41

Three isomers A, B and C (mol. formula C_8 H_11 N ) give the following results: A and C → Diazotization P + Q →[ (ii) oxidation ( KMnO_4+ H^+)] (i)…

Three isomers A, B and C (mol. formula $\displaystyle \mathrm{C}_8 \mathrm{H}_{11} \mathrm{~N}$ ) give the following results : $\displaystyle \mathrm{A}$ and $\displaystyle \mathrm{C} \xrightarrow{\text { Diazotization }} \mathrm{P}+\mathrm{Q} \xrightarrow[\text { (ii) oxidation }\left(\mathrm{KMnO}_4+\mathrm{H}^{+}\right)]{\text { (i) Hydrolysis }} \mathrm{R}$ (product of A) + S (product of C) R has lower boiling point than S $\displaystyle \mathrm{B} \xrightarrow{\mathrm{C}_6 \mathrm{H}_5 \mathrm{SO}_2 \mathrm{Cl}}$ alkali-insoluble product A, B and C, respectively are :
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.