Chemistry · 2019
JEE Main · 12 April 2019, Shift 2 · Q46
Thermal decomposition of a Mn compound (X) at 513 K results in compound Y, MnO_2 and a gaseous product. MnO_2 reacts with NaCl and concentrated H_2…
Thermal decomposition of a Mn compound (X) at $\displaystyle 513$ K results in compound Y, $\displaystyle \mathrm{MnO}_2$ and a gaseous product. $\displaystyle \mathrm{MnO}_2$ reacts with NaCl and concentrated $\displaystyle \mathrm{H}_2 \mathrm{SO}_4$ to give a pungent gas Z. X, Y, and Z, respectively, are:
Official answer
(2)
$\displaystyle \mathrm{KMnO}_4, \mathrm{~K}_2 \mathrm{MnO}_4 \text { and } \mathrm{Cl}_2$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.