Chemistry · 2020
JEE Main · 3 September 2020, Shift 2 · Q49
The volume (in mL ) of 0.1 N NaOH required to neutralise 10 mL of 0.1 N phosphinic acid is \ \ \ \.
The volume (in mL ) of $\displaystyle 0.1$ N NaOH required to neutralise $\displaystyle 10$ mL of $\displaystyle 0.1$ N phosphinic acid is \_\_\_\_.
Official answer
10
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JEE Main 2020 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.