Chemistry · 2019
JEE Main · 10 January 2019, Shift 1 · Q46
The type of hybridisation and number of lone pair(s) of electrons of Xe in XeOF_4, respectively, are:
The type of hybridisation and number of lone pair(s) of electrons of Xe in $\displaystyle \mathrm{XeOF}_4$, respectively, are:
Official answer
(3)
$\displaystyle \mathrm{sp}^3 \mathrm{~d}^2 \text { and } 1$
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JEE Main 2019 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.