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Chemistry · 2021

JEE Main · 31 August 2021, Shift 2 · Q60

The transformation occurring in Duma's method is given below C_2 H_7 N +(2 x+y/2) CuO → x CO_2+y/2 H_2 O +z/2 N_2+(2 x+y/2) Cu The value of y is \ \…

The transformation occurring in Duma's method is given below $$\mathrm{C}_2 \mathrm{H}_7 \mathrm{~N}+\left(2 x+\frac{y}{2}\right) \mathrm{CuO} \rightarrow x \mathrm{CO}_2+\frac{y}{2} \mathrm{H}_2 \mathrm{O}+\frac{z}{2} \mathrm{~N}_2+\left(2 x+\frac{y}{2}\right) \mathrm{Cu} $$ The value of $\displaystyle y$ is \_\_\_\_. (Integer answer)
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.