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Chemistry · 2021

JEE Main · 18 March 2021, Shift 1 · Q58

The total number of unpaired electrons present in the complex K_3[ Cr ( oxalate )_3] is \ \ \ \.

The total number of unpaired electrons present in the complex $\displaystyle \mathrm{K}_3\left[\mathrm{Cr}(\text { oxalate })_3\right]$ is \_\_\_\_.
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.