Chemistry · 2021
JEE Main · 3 August 2021, Shift 2 · Q52
The total kinetic energy of 10 moles of a monoatomic ideal gas at 25^° C in kJ is \ \ \ \. (Nearest integer) [ R =8.314 J K^-1 mol^-1]
The total kinetic energy of $\displaystyle 10$ moles of a monoatomic ideal gas at $\displaystyle 25^{\circ} \mathrm{C}$ in kJ is \_\_\_\_. (Nearest integer)
$$\left[\mathrm{R}=8.314 \mathrm{~J} \mathrm{~K}^{-1} \mathrm{~mol}^{-1}\right]
$$
Official answer
37
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JEE Main 2021 Chemistry question, with the answer from NTA’s final answer key. Where our answers come from.